9 Nov
2005
9 Nov
'05
12:06 a.m.
Well, I didn't explain my self correctly, I didn't
think about a parser such as xerces or xalan but on an
'modeller' for XML technologies such as XMLSpy from
Altova (http://www.altova.com) which I'm using at work
and which is a proprietary application: considering a
DTD (generic structure), XMLSpy is able to give the
equivalent schema (i.e a graphical representation) and
create a basic XML document according to the DTD; I'm
pratically sure that there is an open-source
equivalent of such application (and maybe is it
included in some Linux distributions such as Suse or
Mandrake) but I didn't remember the name. Anyway,
thank you for your help!
M.
--- Alain Knaff <alain(a)knaff.lu> wrote:
On Monday 07 November 2005 23:53, Michel Maria-Sube
wrote:
Hi,
I'm looking for an open-source xml parser, i.e an
equivalent of xml-spy (Altova); any suggestion?
PS: the link for analog software windows/linux
http://linuxshop.ru/linuxbegin/win-lin-soft-en/#42
is
actually down, does anybody know where to find
the
list?
Thank you in advance
MGMS
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There are plenty of XML Parsers available... For
which programming
language do you want it?
For C, there is libxml, included with most Linux
Distributions.
For Perl, there is perl-XML-Parser, also included
with many
distributions (such as SuSE and Fedora). If yours
doesn't have it, you
can download it from CPAN:
http://search.cpan.org/~msergeant/XML-Parser-2.34/
cpan -i XML::Parser
And finally, for Java you can find XML parsers in
the Apache XML and
Xerces projects, but there are plenty of other XML
parsers for Java as
well:
http://xml.apache.org/
http://xerces.apache.org/xerces-j/
Alain